2(x-3)^2-5=27

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Solution for 2(x-3)^2-5=27 equation: 



2(x-3)^2-5=27

We move all terms to the left:

2(x-3)^2-5-(27)=0

We add all the numbers together, and all the variables

2(x-3)^2-32=0

We move all terms containing x to the left, all other terms to the right

2(x-3)^2=32

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